Initialization of a normal array with one default value?

Question

[C++ Notes: Array Initialization](http://www.fredosaurus.com/notes-cpp/arrayptr/array-initialization.html) has a nice list over initialization of arrays. I have a int array[100] = {-1};expecting it to be full with -1's but its not, only first value is and the rest are 0's mixed with random values.The code int array[100] = {0};works just fine and sets each element to 0.What am I missing here.. Can't one initialize it if the value isn't zero ?2: Is the default initialization (as above ) faster than the usual loop through the whole array and assign a value or does it do the same thing?

Answer 1

Actually in your case there isn't a way to initialize all the values of the array to a single value without importing a library. Lets say you had an array of just 5 elements then you could just go ahead and type out the 5 numbers you would like to store. However, you say you have an array of 100 and it would to tedious to type 100 numbers. So you have 2 options here, as you said your first is to use a for loop and fill the array. The second option is to use a library called <algorithm>.

#include <algorithm>

using namespace std;

int main()

{

int sample[100];

fill(sample, sample + 100, -1);

return 0;

}

This would do the same thing. Great question.