How to find the line passing through the given points (-35) and (2,1) ?

Answer 1

using point slope form y - y1 = m (x - x1) or slope infercept form y = mx +b

m = slope

b = y-intercept (0,b)

To find slope use formula m = y2 - y1

x2 - x1

using the points  (-3 , 5) and (2 ,1)

( x1, y1 ) ( x2, y2)

m = (1 - 5) / (2- -3)

m = -4 / 5

Now use point slope form y - y1 = m (x - x1) or slope infercept form y = mx +b to find b

starting with Point slope form

y - 5 = -4/5 ( x - -3)

y - 5 = -4/5 ( x + 3) (if they want point slope form you are done)

if they want slope interdept form continue .....

use this to rewrite in slope infercept form y = mx + b

y - 5 = -4/5 ( x + 3 ) next steo to distribute -4/5

y - 5 = -4/5 x - 12/5 next step add 5 over to other side

y = -4/5 x - 12/5 + 5 combine like terms

y = -4/5 x - 12/5 + 25/5

y = -4/5 x + 13/5 turns into slope intecept form

or ---- 2nd method

start with slope infercept form y = mx +b to find b

y = mx +b

5 = -4/5 (-3) +b

5 = 12/5 + b

5-12/5 = b

25/5 - 12/5 = b

13/5 = b

y = mx + b

y = -4/5 x + 13/5