y = 2x3 - 4
x = 2y3 - 4
x - 4 = 2y3
(x - 4)/2) = y3
y = 3√((x - 4)/2) or ((x - 4)/2)1/3
f-1(x) = 3√((x - 4)/2) or ((x - 4)/2)1/3
Nathalie M.
asked 07/22/19Please explain your steps :))
y = 2x3 - 4
x = 2y3 - 4
x - 4 = 2y3
(x - 4)/2) = y3
y = 3√((x - 4)/2) or ((x - 4)/2)1/3
f-1(x) = 3√((x - 4)/2) or ((x - 4)/2)1/3
Stephen C. answered 07/22/19
SAT Math, Algebra, Trig, PreCalc Tutor
f(x) = 2x^3 - 4 (Given)
y = 2x^3 - 4 (Notational convenience)
x = 2y^3 - 4 (Just exchange x and y to make it the inverse function)
2y^3 = x + 4 (Switching left and right sides, and adding 4 to both sides)
y^3 = (x + 4) / 2
y = 3√((x + 4)/2), or [(x + 4)/2]1/3 (Take the cubed root of both sides)
f-1(x) = [(x + 4)/2]1/3 (Give our result the proper inverse-function notation)
Use the desmos graphing calculator to verify that the function and the inverse are mirror images, with respect to the line y=x ... (why?)
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Mark M.
07/22/19