Given that tan(θ)=6, what is tan(2θ)?

Question

am i using the formula correctly if i get

2tan(6)/1-tan^2(6)

Answer 1

You're close, but you need to substitute 6 for tan θ

tan 2θ = 2 tanθ/1-tan²θ

Since tan θ = 6

tan 2θ = 2(6)/ 1 - 6² = -¹²/₃₅