
Mark M. answered 07/25/19
Tutor
5.0
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Mathematics Teacher - NCLB Highly Qualified
cot 2θ = (A - C) / B
cos 2θ = 1 / √3
tan 2θ = √3
θ2 = π/3
θ = π/6
sin π/6 = 1/2
cos π/6 = √3 / 2
x = x' cos π/6 - y' sin π/6
y = x' sin π/6 - y' cos π/6
x = x'√3 / 2 - y' / 2
y = x' / 2 - y'√3 / 2
Now substitute into original equation and simplify into standard form