
Stanley P. answered 07/17/19
Experienced Tutor: Elementary Math, Algebra 1 & 2, Trig and Calculus
You want to evaluate each part separately and plug in the right value for x.
f(x+2) = 3(x+2)2+4 (x+2)2 = x2+4x+4
= 3(x2+4x+4)+4
= 3x2+12x+12+4
= 3x2+12x+16
f(x) + f(2) =
[ 3x2+4 ] + [ 3(2)2+4 ] =
[ 3x2+4 ] + [ 16 ] =
3x2+4 + 16 = 3x2+20
Hope this helps.