What is the specific heat capacity of silicon if it takes 192j to raise the temperature of 45.0j of si by 6.0c

Answer 1

Let me make an assumption here. 45 j of Si should be 45 gram. Given that, the specific heat capacity is the amount of heat required to raise 1 gram of a substance by one degree C.

Thus 192 j = c *6/45. or c = 192/(6*45)/ = 0.711 j/g*C

Answer 2

I think you might mean 45 kg of Si.

Specific heat is the energy (in kilo-joules) required to raise 1 kg of material by 1 Kelvin**

E = energy

T = temp rise

m = mass

SH = E / (T * m) = 192J / (6 * 45kg) = 192 / 270 = 0.71

Thankfully, that is similar to the value given here:

https://www.engineeringtoolbox.com/specific-heat-solids-d_154.html

**A delta of 1 Kelvin is the same as a delta of 1C