if m = mass of the box (26 kg), c = angle of inclination (31 degrees), g = acceleration of gravity (9.8 meters/sec2)
Then F = ma = 161 - mgsin(c) = 161 - (26)(9.8)sin(31) = 29.77 Newtons
29.77 = 26a so a = 1.145 m/s2
Syd T.
asked 06/30/19If a 26 kg box sits on a 31 degree hill, and a 161 N force pulls uphill. Do the same thing as the last problem, but now use ∑F = ma to find the acceleration of the box.
if m = mass of the box (26 kg), c = angle of inclination (31 degrees), g = acceleration of gravity (9.8 meters/sec2)
Then F = ma = 161 - mgsin(c) = 161 - (26)(9.8)sin(31) = 29.77 Newtons
29.77 = 26a so a = 1.145 m/s2
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