if mass (m) of the block (3.3 kg), g = acceleration due to gravity (9.8 meters/sec2), u = coefficient of friction (.1), c = angle of inclination (11.5 degrees) and we assume that the block is traveling up the hill due to the 40 N force. a = acceleration of the block (meters/sec2)
The F (sum of forces) = ma
F = 40 - (3.3)(9.8)sin(c) - (.1)(3.3)(9.8)cos(c) = ma = 3.3a
or 30.38 = 3.3a then a = 9.2 m/s2