Patrick B. answered 06/28/19
Math and computer tutor/teacher
1)
a)
3y + 4x = 12, has slope -4/3
-6y = 8x+1 has slope -8/6 = - 4/3
the slopes are the same so the lines are parallel
b) 3y +x = 12, has slope -1/3
y = 8x+1 has slope 8
the slopes are different, not negative reciprocals,
so the lines are neither parallel nor perpendicular;
they will intersect at a unique point
c) 4x - 7y = 10 , has slope 4/7
7x + 4y = 1 has slope -7/4
the slopes are negative reciprocals, so the lines are
perpendicular
2) at the top of the building, t=0, so 8 feet
max occurs at -b/2a = -24/(2*-4.9) = 2.448979591835...
h(2.44...) = 37.38775
3) f(75) = 25
f(78) = 28
f(81) = 31
slope is 1.
y = x+ 50 is the linear equation.
Noemi Y.
Question 3 ask for the max number of bushes, so we need to use quadratic formula and find the vertex we can write the equitation as y- 20 = -3 ( x * 75) y = -3x + 245 for this, you can calculate h = -b/2a -> 275/-2(-3) = 40.8 There is no 40.8 tree you can plant 41 trees.02/09/21
Noemi Y.
2 question h(t) = -4.9t^2+ 24t+8 ->building is 8m high to calculate the max height again we need to calculate the vertex h= -b/2a= -24/-4.9*(2)= 24/9.8 k(24/9.8) ->f(24/9.8) = -4.9(24/9.8)^2+ 24(24/9.8)+8 = 37.38 feet02/09/21
Wilcox A.
Hello Patrick, Thanks for helping me out with the answers. I do not understand how you calculated and arrive at your answers in number 2 and 3. I am really confused. Please help explain a bit more.07/02/19