Legend B.

asked • 06/27/19

IMPOSSIBLE QUESTION!!! I have the question in the link below.

https://docs.google.com/document/d/1-7UkQpvidcO4-gMiuDlPSLCV7AUchLWHWAt2D1P2xwM

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Doug C. answered • 06/28/19

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Sort of rushed through the video to keep it close to 5 minutes.


Also here is the Desmos link


Attach this value /up05uclhv7 to the Desmos online graphing calculator UR (desmos.com/calculator)



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Legend B.

Thank you so much
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06/28/19

Mark M. answered • 06/28/19

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The rectangles are 2 units wide and 4 units high (that's in the problem).

Now count to determine the coordinates of the point at the intersection of the line and the upper right corner of the right most rectangle.


Use the slope formula.

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Legend B.

But it the line doesn’t intercept the top right corner
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06/28/19

Doug C.

If it did intersect the upper right corner the area under the line from -4 to 10 would be 42, but it must be 44 (picture moving one rectangle from above the line the the spot at (8,0). So the intersection point must be above the point (10,6). From here I will give you a hint. Let p = the distance along the vertical line x = 10 that is above the corner of the rightmost rectangle. When you draw the line from (-4,0) through that point (10, p+6) a little rectangle is created in the upper right corner. Use similar triangles to get the base and height of the little triangle, followed by a formula for the area of that triangle in terms of p. Then the equation that follows is this. Area big triangle - area of little triangle = 44. You can solve that for p. Finally calculate the slope from (-4,0) to (10, p+6).
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06/28/19

Doug C.

Let me know if that is enough info to solve the problem. If not I will create a video answer.
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06/28/19

Legend B.

Would you please create a video because I’m not following and I would really appreciate it?
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06/28/19

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