
Rachael T. answered 01/10/15
Tutor
5.0
(205)
Math & Teaching Specialist: Youth-friendly, patient, and encouraging
For #1: Using substitution, solve the second equation for x or y. I'll solve for x.
Add 7y to both sides, to get x alone. x=7y - 15. Then substitute that in for x in the first equation.
4(7y-15) -7y = 3
28y -60 -7y =3
21y = 63
y = 3
For #2: Using elimination, add the second equation to the first, to get rid of the 2y.
3x + 2y = -15
x - 2y = 19
4x + 0 = 4
x = 4