ln(x+1) + ln(x-1) = ln{ (x+1)(x-1) } = ln(x2-1) so ln(x) - ln(x2-1) = ln(x/(x2-1))
Nia H.
asked 06/25/19Condense the expression to a single quantity
Lnx -[ln(x+1) + ln (x-1)
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