
Patrick B. answered 06/18/19
Math and computer tutor/teacher
Car A: 55(t/60) = (11/12)t
Car B: 30(t/60) = (1/2)t
The distance function, per pythagorean, is
sqrt { [(11/12)t ]^2 + [ (1/2)t]^2 } =
sqrt { [ (121/144) t^2 + (1/4) t^2 ] } =
sqrt { [ (121/144)t^2 + (36/144) t^2 ] }
sqrt{ (157/144) t^2 ]
sqrt(157)/ 12 * t
Quick check:
t=1 hour = 60 min
car A is 55 miles north and bar B is mile miles east.
sqrt( 55^2 + 30^2) = sqrt( 3025 + 900) =
sqrt( 3925) = sqrt( 157*25) = 5 * sqrt(157)
Per the formula, for t=60, sqrt(157)/12* 60 = 5 * sqrt(157)
so yes it checks