HELP PLS this queation is difficult

Question

An airplane takes off at an angle of 75° from its starting point. When the plane has traveled a total distance of 600 feet, its vertical height above the runway to the nearest foot is _____.

Answer 1

Lets call y the vertical distance traveled from runway and z the distance the plane actually traveled.

/ |

/ |

z-> / |

/ |

/ | <---- y

/ |

/ _|

/__ |_|

^The runway

We are given that the angle between runway and the trajectory of the plane is 75°. We are also given that z = 600 ft.

sin(θ) = opposite/hyponesue

sin(75°) = y/z

sin(75°) = y/600

y = 600 sin(75°) = 579.56 ft

Answer 2

A picture is worth a thousand words

Using trigonometric ratios sin = opposite / hypotenuse

So Sin 75 = x / 600. So x = 600 * sin 75. X= 579.5 or approx 580 feet

⁄

⁄. Remember to put 600 times rather than sin 75*600. The calculator will give you sin 45000.

⁄

⁄. You should be able to upload an image here.

—————