please help!

Question

What is the vertex and y-intercept of g(x)=3x2(squared)+2x+1?

Answer 1

 

g(x)=3x²+2x+1

 

Vertex ( -b/2a ; g[-b/2a] ) where a = 3 and b= 2  from g(x)=ax²+bx+c

 

Vertex ( -2/6 ; g(-1/3) )       g(-1/3) = 3(1/9)+2(-1/3)+1 = 1/3 - 2/3 + 3/3 = 2/3

 

Vertex ( -1/3 ; 2/3 )

 

y-intercept ( 0 ; g(0) )           g(0) = 0 + 0 + 1 = 1

 

y-intercept ( 0 ; 1 )

 

Both vertex and y-intercept are points, each with 2 coordinates, always remember that Morgan !