The perimeter of an NBa-sized basketball court is 288 ft. The length is 44 ft longer then the width. Find the dimensions of the court.

Question

The perimeter of an NBa-sized basketball court is 288 ft. The length is 44 ft longer than the width. Find the dimensions of the court. 

Answer 1

Hi Dylan

 

Perimeter = 2l + 2w    //l=length, w=width

 

l = 44 + w

 

Now substitute 44 + w in place of l in the above equation and you have 

 

2(44 + w) + 2w = 288

 

=> 88 + 2w + 2w = 288

 

=> 88 + 4w = 288

 

=> 4w = 200

 

=> w = 50 and l = 44 + 50 = 94

 

2*94 + 2*50=288