find the number whose 7th part multipied by its 11 part gives 1,232

Question

explain sir

Answer 1

The mention of 7th part and 11th part implies that the number, N, is divisible evenly by both 7 and 11.   Since both 7 and 11 are prime numbers,  this implies that  N = 7 x 11 x c   = 77 c    for some integer c.

 

(N/7) x (N/11)  =  1232     So

 

(11 c) x (7 c) =  1232     So   77 c²  = 1232      Solving for c  yields   c = 4 

 

So finally, the number N    = 77 c =  308 

 

It is easy to check that this works:

 

(308/7) x (308 /11)  does indeed evaluate to  1232