the length of a rectangle is 2 in longer than its width. If the perimeter of the rectangle is 24 in, find its area

Question

please help me

Answer 1

Hi Christian,

 

Lets define width as W and length as L. The first part of the question says that the length is 2in. longer than the width. Therefore:

 

L = 2 + W

 

The 2nd part of the question states that the perimeter is 24in. So lets set up an equation for the perimeter:

 

P = 2L + 2W

24 = 2L + 2W

 

Now substitute in your 1st equation: 24 = 2( 2 + W ) + 2W

Solve for W. Now you should be able to solve for L. After, you know that Area = LxW so now you have your answer!