Sara S.

# Calculus Triangle Related Rate

So I have a problem where there is a right triangle with the height (4500ft) and the rate at which the angle is changing (pi/180radians per second) and I need to find the ground speed.
I figured out that the ground speed dx/dt=-4500csc^2(theda) d(theda)/dt
But after this I am stuck. I really need help because I just don't get how I'm supposed to find the speed, please help as soon as possible I am forever thankful.
Also I kind of got an answer of 1272 mph, is there any chance that is even possibly right?

## 2 Answers By Expert Tutors

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Imtiazur S. answered • 01/02/15

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Calculus - The mother of all sciences

Francisco P. answered • 12/15/14

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Well-Versed in Calculus

Imtiazur S.

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dx/dt = -4500ft csc2θ dθ/dt = -4500ft csc2(π/2) (π/180 sec) = -78.54 ft/sec.  How did you get π/2 in the csc2(π/2)?
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01/02/15

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