Natural Log Base Equation

Question

7 e^x = -2 e^x + 5

 

Find x where e is the base of a natural log

Answer 1

7e^x = -2e^x + 5

9e^x = 5

e^x = 5/9

ln e^x = ln (5/9)

x ln e = ln 5 - ln 9

x = ln 5 - ln 9

x ≈ 1.609 - 2.197

x ≈ -0.588