Rewrite the complex number in polar form, z=r(cos(theta) + i sin (theta)), z =2 - 2i = ?

Answer 1

z=a+bi

z=r(cosΘ+isinΘ) is the complex number in polar form

r=lzl=√(a^2+b^2)=√(2^2+[-2]^2)=√8=2√2=2.828

Θ=tan^-1(b/a)=tan^-1(-2/2)=tan^-1(-1)=-45º=-0.785 (use radians and not degrees)

z=2.828(cos[-0.785]+isin[-0.785])