
Jacob P. answered 05/09/19
A tutor that adapts to your learning needs.
First do you mean:
(n*3^n-1)/(2^2*n) ?
If so then,
Or do you mean:
(n*3^(n-1))/(2^(2*n)) ?
If so then,
Jakob W.
asked 05/05/19I have the power series (n3^n-1)/(2^2n) going from 1 to infinity. How do I find the exact value for the series. I believe that we just use a power series function that we already know and based off of that we need to manipulate it in order to find a function where we can plug in x. HOW DO I DO THIS!
Jacob P. answered 05/09/19
A tutor that adapts to your learning needs.
First do you mean:
(n*3^n-1)/(2^2*n) ?
If so then,
Or do you mean:
(n*3^(n-1))/(2^(2*n)) ?
If so then,
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