Jacob P. answered • 05/09/19

A tutor that adapts to your learning needs.

First do you mean:

(n*3^n-1)/(2^2*n) ?

If so then,

Or do you mean:

(n*3^(n-1))/(2^(2*n)) ?

If so then,

Jakob W.

asked • 05/05/19I have the power series (n3^n-1)/(2^2n) going from 1 to infinity. How do I find the exact value for the series. I believe that we just use a power series function that we already know and based off of that we need to manipulate it in order to find a function where we can plug in x. HOW DO I DO THIS!

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Jacob P. answered • 05/09/19

Tutor

New to Wyzant
A tutor that adapts to your learning needs.

First do you mean:

(n*3^n-1)/(2^2*n) ?

If so then,

Or do you mean:

(n*3^(n-1))/(2^(2*n)) ?

If so then,

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