Patrick B. answered 05/04/19
Math and computer tutor/teacher
1) The right triangle has leg on the positive x-axis and other leg going down ( negative y direction)
the angle at the origin is 30 degrees, so it is 30-60-90 right triangle.
This forces the leg measures to be 1 and sqrt(3), and the hypotenuse to be 2.
The sine of this angle is -sqrt(3)/2.
The other way to see it is to find where the circle and the angle, when promoted to a line, intersect.
The equations are x^2 + y^2 = 1 vs. y = -sqrt(3) * x. THe solution is x=1/2, y =-sqrt(3)/2
2)
cos 2x = 1/2
cos T = 1/2
T = 60 degrees, 300 degrees
x = 30 degrees, 150 degrees
3)
cos(x+x) = cosx*cosx - sinx*sinx = <-- double angle formula as suggested by the hint
cos^2 - sin^2 =
1 - sin^2 - sin^2 = <--- cos^2 = 1 - sin^2
1 - 2*sin^2