the first part is a standard exponential growth problem where Final amount = Initial amount x r^t so
20000= A x (1.08)^10
A = 20000/(1.08)^10
A = 9263.87
The second part is a continuous decay problem where
Final amount=Initial amount x e^rt
First we must calculate r(decay constant )
We know that in 5730 years there will only be 1/2 of the initial amount( that is the definition of half life) so
0.5= e^5730r. now take the natural log of both sides so
ln(0.5)= 5730r = -0.000120968
r=ln(0.5)/5730. We will use this value to now calculate the number of years(t) for sample to decay to 20 percent of its initial amount so
(0.2) = e^rt. Again take natural log of both sides to solve for t
ln (0.2)= rt
t= ln0.2/rt
t= -1.6094379/-0.000120968
t= 13304.66 years