Philip P. answered 12/05/14
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The graph has zeros at x = 0, 1, 3, 6. Hence the basic function is:
f(x) = ax(x-1)(x-3)(x-6)
where a is a constant. To find the value of a, plug in the known point, (-1,4):
4 = a(-1)(-1-1)(-1-3)(-1-6)
4 = 56a
1/14 = a
So the polynomial is:
f(x) = (1/14)(x)(x-1)(x-3)(x-6) = (1/14)x4 - (5/7)x3 + (17/14)x2 - (9/7)x
