The perimeter of a rectangle is 92 feet Find its dimensions assuming that its length is 5 feet less than twice its width The width is and length is

Question

The perimeter of a rectangle is 92 feet Find its dimensions assuming that its length is 5 feet less than twice its width The width is and length is

Answer 1

Let l = the length of the rectangle and w = the width of the rectangle. Then we have 2 equations:

1) 2 x l + 2 x w = 92 and 2) l = 2 x w - 5 Substituting the equation for l into equation 2) we have

2 x ( 2w - 5 ) + 2 x w = 92 Simplifying

4 x w - 10 + 2 x w = 92 So 6 x w = 102 and

w = 17 So l = 2 x 17 - 5 = 29

Check 2 x 29 + 2 x 17 = 58 + 34 = 92

Answer 2

Let x = length and y = width. Then 2x +2y =92 and x= 2y -5 or x - 2y= -5. Use the two equations x + y = 46 and x -2y = -5> Subtract the first equation from the second one to obtain -3y = -51 or y = 17 and x = 29. So the width is 27 and the length is 29.