Cagri S. answered 04/26/19
Knowledgeable and Experienced Math Tutor Specializing Calculus
This is actually a calculus problem involving related rates which is about differentiation.
V=1/3*Π*r2*h
dv/dt=1/3*∏*2r*h
dv/dt=1/3*2*10*20*40 so the if you do the necessary calculation you get the rate of change of volume around 1600 cm3 per second