
Mark M. answered 12/02/14
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Mathematics Teacher - NCLB Highly Qualified
s = speed of car 2
s + 14 = speed of car 1
r · t = d
t = d / r
For car one
t = 162 / (s + 14)
For car two
t = 120 / s
The two times are equal.
162 / (s + 14) = 120 / s
162s = 120(s + 14)
162s = 120s + 1680
42s = 1680
s = 40
Car one goes 54 mph and car two goes 40 mph.