height and seconds

Question

If an object is thrown upward with an initial velocity of 256 ​ft/second, then its height after t seconds is given by what equation?

Answer 1

Δx=v₀t+(1/2)at²

v₀=256ft/s

a=-9.8m/s²=-32ft/s²

Δx=(256ft/s)t-(1/2)(32ft/s²)t²

Δx=(256ft/s)t-(16ft/s²)t²=(16ft/s)((16)t-(1/s)t²)