f(x) = (e^3x)sin(3x) f(0) = 0
f'(x) = (3e^3x)sin(3x) + 3(e^3x)cos(3x) f''(0) = 3
so, the linearized function is f(x) = f(0) + f'(0)x = 3x
assuming you are using the Taylor's series truncated prior to the powers of x!
f(x) = (e^3x)sin(3x) f(0) = 0
f'(x) = (3e^3x)sin(3x) + 3(e^3x)cos(3x) f''(0) = 3
so, the linearized function is f(x) = f(0) + f'(0)x = 3x
assuming you are using the Taylor's series truncated prior to the powers of x!
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