How do I find the final mixture required and percent of acid in final mixture required and the amount of 25% and 50% of the solution in liters?

Question

Find how much of each solution is required to obtain 25% solution and 50% solution and find the amount of final mixture required and percent of acid in final mixture required

Answer 1

THe problem is not stated clearly.

25% solution is mixed with 50% solution to obtain and certain percentage solution.

The amount and % acid proof must be given.

All that can be said is:

x L of 25% solution is mixed with y liters of 50% solution to make (x+y) liters of a t% solution

If known, then N is the number of liters of the final solution.

Then N = x+y and

there is (25x + 50y) / (x+y) % of acid in the final solution.

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