
Philip P. answered 12/02/14
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The largest of three consecutive positive numbers is x, so the numbers are (x-2), (x-1), and x. The square of this number (x) exceeds the sum of the other two numbers by 38:
x2 = (x-2) + (x-1) + 38
x2 = 2x + 35
x2 - 2x - 35 = 0
Factors to:
(x-7)(x+5) = 0
x = 7 and -5
Since the problem states that a is positive number, the answer is x = 7
Check:
x2 = (x-2) + (x-1) + 38
72 = 5 + 6 + 38
49 = 49
Check!