Victoria V. answered 04/19/19
20+years teaching PreCalculus & all Surrounding Topics
Parallel vectors will be multiples of each other.
Perpendicular vectors will have a dot product of 0.
Let v1 = <a,b> and v2 = <c,d>
v1 || <-5,1> means v1 = N <-5,1> = <a,b>
So a = -5N and b=N (keep this handy for later)
v2 • <-5,1> = 0 (because they are perpendicular)
So <c,d> • <-5,1> = -5c + d = 0 or d = 5c (keep this handy for later)
v1 + v2 = <a,b> + <c,d> = <3, -1>
So a + c = 3 and b + d = -1 (keep this handy - putting all together now)
Substitute -5N for a. Substitute N for b. Substitute 5c for d.
This gives us a system of equations with two equations and 2 unknowns:
-5N + c = 3
N + 5c = -1
Multiply everything in the bottom equation by 5
-5N + c = 3
5N + 25c = -5
Now add vertically, eliminating the variable N and finding
26c = -2
or
c = -1/13
Now we work our way backwards.
-5N + c = -5N + (-1/13) = 3
-5N = 40/13
(-1/5) (-5N) = (40/13)(-1/5)
and N = -8/13 and b = N so b = -8/13
d = 5c so d = -5/13
a = -5N, so a = 40/13
So the two vectors are:
v1 = < 40/13, -8/13 >
v2 = < -1/13, -5/13 >