for f(x) =4/xsq -1 we have vertical asymptotes at -1 and 1 so domain is ( -infinity,-1) (-1,1), (1-infinity)
for g(x)=x+1 domain is all reals(-infinity,infinity)
H C.
asked 04/12/19f(x)= 4/x²-1 and g(x)= x+1
for f(x) =4/xsq -1 we have vertical asymptotes at -1 and 1 so domain is ( -infinity,-1) (-1,1), (1-infinity)
for g(x)=x+1 domain is all reals(-infinity,infinity)
Mark M. answered 04/13/19
Retired math prof. Very extensive Precalculus tutoring experience.
f(x) = 1 / (x2-1)
g(x) = x + 1
(fog)(x) = f(g(x)) = f(x+1) = 1 / [(x+1)2-1] = 1 / (x2+2x)
domain(fog) = {x l x ε dom(g) and g(x) ε dom(f)} = {x l x+1 ≠ ±1} = {x l x ≠ 0, -2}
(gof)(x) = g(f(x)) = g(1 / (x2-1)) = 1 / (x2-1) + 1 = x2 / (x2 - 1)
dom(gof) = {x l x ε domf and f(x) ε domg} = {x l x ≠ ±1}
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