Marti R. answered • 04/11/19
I was called The Algebra Genius by one student!
When x < 0, x is negative. At y = 8, y is, of course, positive. So you are looking for the quadrant where x is negative and y is positive.
Quadrant 1 is the upper right quadrant, and both x and y are positive. Moving counter-clockwise, Quadrant two is still above the x-axis, where y is positive, but now to the left of the y-axis, x is negative. Continuing counter-clockwise, you are now in the 3rd Quadrant, still to the left of the y-axis, where x is negative, but now below the x-axis, where y is negative. One more move, to the right, and you find yourself in the 4th quadrant, to the right of the y-axis, where x is positive, but still below the x-axis where y is negative.
The answer is in there -- can you find it?
