Perform the operation and write the result in standard form. 1+i/i-8/8-i

Answer 1

Not sure if this is (1+i)/[(i-8)/(8-i)] --- (1) or [(1+i)/(i-8)]/(8-i) --- (2) or something else.

Assuming it is (1):

(1+i)/[(i-8)/(8-i)] = (1+i)(8-i)(-8-i)/65 = (9+7i)(-8-i)/65 = (79-65i)/65 = 79/65 - i

Assuming it is (2):

[(1+i)/[(i-8)]/(8-i) = [(1+i)/[(-8+1)]/(8-i) = (1+i)/(-63) = = -1/63 - 1/63 i

Answer 2

1 + i/i - 8/8 - i

1 + 1 - 1 - i

1 - i

No grouping symbols and parenthesis....

Now WITH the parenthesis:

(1+i)/(i-8) * (8-i) =

(1+i) * -1 =

-1 - i