William W. answered • 04/08/19
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Based on the comments, the correct question is:
Given f(x) = -3x³ + 14x² + 6x - 24, write f(x) as (x − k) q(x) + r(x) where k = 3 +√3
To do this problem, use synthetic division to divide (x - (3 + √3)) into -3x³ + 14x² + 6x - 24. Doing so will result in a quotient, q(x), of: -3x^2 + (5 - 3√3))x + (12 - 4√3) with a remainder, r(x) of 0 so:
f(x) = (x - (3 + √3))[-3x^2 + (5 - 3√3))x + (12 - 4√3)] + 0
Doug C.
What am looking for is the answer to f(x)=?04/08/19
William W.
Maybe I'm not understanding the question. Is k equal to two different values, 3 and sqrt(3) or is it supposed to be one value, 3 + sqrt(3)?04/08/19
William W.
If its a single value of k where k = 3 + sqrt(3), then when you do synthetic division, you get f(x) = [x - (3 + sqrt(3))][-3x^2 + (5 -3sqrt(3))x + (12 - 4sqrt(3)] + 0 (remainder is zero)04/08/19
Doug C.
Write the function in the form f(x) = (x − k)q(x) + r(x) for the given value of k. f(x)= 3x³+14x²+6x-24, k=3+√3 (the symbol before the 3 is supposed to have the 3 inside of it. But I do not know how to make that symbol with my keyboard.)04/08/19
William W.
I updated my answer in the original post. As I mentioned above, the answer when k = 3 + √3, is: f(x) = (x - (3 + √3))[-3x^2 + (5 - 3√3))x + (12 - 4√3)] + 0 The divisor is (x - (3 + √3)), q(x) = [-3x^2 + (5 - 3√3))x + (12 - 4√3)] and r(x) = 004/08/19
Doug C.
So what is the final answer because I entered that equation and it is not correct.04/08/19