
Mark M. answered 11/28/14
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Mathematics Teacher - NCLB Highly Qualified
sec2t = tan2t + 1
2tant + tan2t + 1 = 0
tan2t + 2tant + 1 = 0
(tant + 1)2 = 0
tant = -1 second and fourth quadrants
t = 3π/4
t = 7π/4