
Francisco P. answered 11/26/14
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Rigorous Physics Tutoring
Let L = the original distance from the base of the tower and H = the height of the tower.
tan(29°20') = H/L [1]
tan(57°30') = H/(L - 24.0) [2]
Solving for L in [1] and substituting it in [2]:
L = H/tan(29°20')
[H/tan(29°20') - 24.0]tan(57°30') = H
Solving for H:
H[tan(57°30')/tan(29°20') - 1] = 24.0 tan(57°30')
H = 24.0 tan(57°30') / [tan(57°30')/tan(29°20') - 1] = 21.0 m = H
L = 37.4 m