If x = 1.3 then y = 3.7828.
2x dx/dt + 2y dy/dt = 0
2(1.3) dx/dt + 2(3.7828)(3) = 0 and solve for dx/dt
dx/dt = -8.7295
Evan M.
asked 04/03/19Let x^2 + y^2 = 16, and suppose that dy/dt = 3 when x = 1.3 and y > 0
Then dx/dt =
If x = 1.3 then y = 3.7828.
2x dx/dt + 2y dy/dt = 0
2(1.3) dx/dt + 2(3.7828)(3) = 0 and solve for dx/dt
dx/dt = -8.7295
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