
Francisco P. answered 11/26/14
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Rigorous Physics Tutoring
Volume = π(radius)2(height) for cylindrical cans.
For the relationship between large (R, H, V) and small cans (r, h, v) we can write
R = (1 + 25%)r = 1.25r
H = (1 + 25%)h = 1.25h
The volume of the small can is v = πr2h and the volume of the large can is V = πR2H.
V can be written in terms of r, h, and v:
V = π(1.25r)2(1.25h) = (1.25)3πr2h = 1.253v = 1.953 v
The volume of the larger can is (1.953v - v)/v x 100% = 95.3% more than the volume of the smaller can or almost twice the volume.