Mark M. answered 11/25/14
Tutor
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Mathematics Teacher - NCLB Highly Qualified
I call this a doughnut hole problem. First find the size of the doughnut - the garden with the border - and then subtract the hole - the garden.
b = width of the border
The dimensions of the garden with the border is 9 + 2b by 22 + 2b (2b because the border is on both sides)
(9 + 2b)(22 + 2b)
198 + 44b + 18b + 4b2
198 + 62b + 4b2
Now subtract the garden that is 9(22) or 198.
62b + 4b2 = 312 The area of the border must equal the amount of seed
4b2 + 62b - 312 = 0
(b - 4 )(4b + 78) = 312
b ∈{4, -78}
Length cannot be negative
The width of the border is 4 feet.