Inactive Tutor answered 03/30/19
You have zeroes of 2 (multiplicity 2) and 3 ± 3i. Thses zeros give you factors of:
(x-2)*(x-2)*(x-3-3i)*(x-3+3i) (note x MINUS 3 ...)
See if this gives you the correct answer.
Hope this helps!
Blaze R.
asked 03/29/19Hello! I am currently stuck on a homework question and I keep getting it wrong. Here is what the question is asking:
Find a polynomial with integer coefficients that satisfies the given conditions.
R has degree 4 and zeros 3 − 3i and 2, with 2 a zero of multiplicity 2.
Here is the work that I have done:
(x-2)(x-2)(x+3+3i)(x+3-3i)
(x-2)(x-2)[(x+3)+3i][(x+3)-3i]
(x-2)(x-2)[(x+3)2-(3i)2]
(x-2)(x-2)[(x+3)2-(-9)]
(x2-4x+6)(x2+6x+18)
x4+2x3-2x2-48x+72
So R(x)=x4+2x3-2x2-48x+72
When I go to check it it says it's wrong. I have checked the math over and over and have done it 4 time but end up with the same answer. I appreciate your time in advance!
Inactive Tutor answered 03/30/19
You have zeroes of 2 (multiplicity 2) and 3 ± 3i. Thses zeros give you factors of:
(x-2)*(x-2)*(x-3-3i)*(x-3+3i) (note x MINUS 3 ...)
See if this gives you the correct answer.
Hope this helps!
Inactive Tutor answered 03/29/19
You did make a minor error. What is (x-2) (x-2)? It is x2 - 4x + 4, not x2 - 4x + 6 Plug the corrected value in and I get:
x4 - 2x3 - 2x2 - 48x + 72 Hope this helps. Sometimes you get so close to a problem, you repeat the same error over and over. You had the basics down cold!!!
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.