How do you set, clear, and toggle a single bit?

Question

How do you set, clear, and toggle a bit in C/C++?

Answer 1

char n = 7; // 00000111

// setting 4th bit from right (bitwise OR)

// 00000111 (7) | 00001000 (8) == 00001111 (15)

n = n | 8; // n == 15

n = 7;

// clearing 3rd bit from right (bitwise AND)

// 00000111 (7) & 11111011 (251) == 00000011 (3)

n = n & 251; // n == 3

n = 7;

// toggling 2nd bit from right (bitwise XOR)

// 00000111 (7) ^ 00000010 (2) == 00000101 (5)

n = n ^ 2; // n == 5

Answer 2

It's fairly easy, at least in C++ - just use the bitwise & (AND), | (OR) and ^ (XOR) operators.

using namespace std;

int main() {

unsigned int num1 = 10; // 10 = 0000 1010

unsigned int num2 = 12; // 12 = 0000 1100

int num3 = 0;

num3 = num1 & num2; // 8 = 0000 1000

num3 = num1 | num2; // 14 = 0000 1110

num3 = num1 ^ num2; // 6 = 0000 0110

return 0;}