
Mark M. answered 11/23/14
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This has two parts, theA interest on the initial deposit ($750) and the interest on the recurring deposits.
The amount on the first deposit:
Since in the first year, Raul puts in $2,250
A = p(1 + r/n)nt , where A = amount at the end, r is the rate, n is number times deposit\calculated, t = time in years.
A = 2250 (1 + 0.08)40
A = 2250 (1.08)40
A = 2250 · 21.72
A = 48870
A = d{((1 + r)t - 1) /r}, where d = the monthly deposit. Here t = 34 since the first three deposits were included above.
A = 750{((1 + 0.08)34 -1) / 0.08}
A = 750 {(13.6901 - 1) / 0.08}
A = 750 (12.6901 / 0.08)
A= 750 · 158.62
A = 118970
The total amount is $167,840.