Christopher R. answered 11/22/14
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Mandy, to show the work in determining the limit as xy approaches (0,0). Note: It looks like the limit does exist because it doesn't approach a number divided by zero.
lim→(0,0) (x^2+y^2)/(x^2+y^2+1)^(.5)-1=(0^2+0^2)/(0^2+0^2+1)^(.5)-1=0/(0+1)^(.5)-1 =0/1^(.5)-1=0-1=-1
Hope this helps.