Determine the concentration of a solution prepared by diluting 25.0 mL of a stock 0.188 M Sr(NO3)2 solution to 150.0 mL.
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2 Answers By Expert Tutors
Sandra H. A Patient, successful and effective professional.
The solution is being diluted 150/25=by a factor of 6
So the molarity will go down by a factor of 6= 0.188M/6=0.0313M
Certified Stevenson AP Biology Teacher/STEM Research Coordinator
Use the formula M1V1 = M2V2
M= Molarity (moles/Liter)
V= Volume (in Liters)
(.188)(.025) = (x)(.150)
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