Determine the concentration of a solution prepared by diluting 25.0 mL of a stock 0.188 M Sr(NO3)2 solution to 150.0 mL.

Question

Help please explain I am trying to learn!!

Answer 1

The solution is being diluted 150/25=by a factor of 6

So the molarity will go down by a factor of 6= 0.188M/6=0.0313M

 

 

Answer 2

Use the formula M1V1 = M2V2

 

M= Molarity (moles/Liter)

V= Volume (in Liters)

 

(.188)(.025) = (x)(.150)