Physics space station question

Question

A space station has a diameter of 340 meters and the occupants who are at the other rim have an acceleration of 6.2 m/s^2. What is the angular velocity of the station?

Answer 1

a=v²/r so v=(a*r)^1/2 once you know v you can calculate ω from v=rω, ω=v/r. Just plug in r=340/2m and a=6.2m/sec²

Let me know if you have questions

Jim