Since the cotan function is 1/tan then wherever tan(x) =∞ the cotan(x)=0 and tan(π/2) and tan(3π/2)→∞ so cotan of those angles are 0
Jim
Since the cotan function is 1/tan then wherever tan(x) =∞ the cotan(x)=0 and tan(π/2) and tan(3π/2)→∞ so cotan of those angles are 0
Jim
Reyn A. answered 03/20/19
ChemE Grad Specializing in Science and Test Prep Skills
First, break down this problem by expanding cot(x):
cot(x) = 1/tan(x) = cos(x)/sin(x)
Now, find sin and cos values for pi/2 and 3pi/2
sin(pi/2) = 1, sin(3pi/2) = -1
cos(pi/2) = 0, cos(3pi/2) = 0
Now you can go back to the cot equation and solve:
cot(pi/2) = 0/1 = 0
cot(3pi/2) = 0/-1 = 0
Patrick B. answered 03/17/19
Math and computer tutor/teacher
tan(pi/2) is undefined, so the contangent is zero
same is true for 3*pi/2
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